In an ap the sum of first 10 terms is - 150
WebApr 15, 2024 · Best answer Let d be the common difference. Given: first term = a = -4 last term = l = 29 Sum of all the terms = Sn = 150 Sn = n/2 [a + l] 150 = n/2 [-4 + 29] n = 12 There are 12 terms in total. Therefore, 29 is the 12th term of the AP. Now, 29 = -4 + (12 – 1)d 29 = -4 + 11d d = 3 The common difference is 3. ← Prev Question Next Question → WebYou would do the exact same process, but you would have to SOLVE for "n" (number of terms) first. To do so, you must start with the arithmetic sequence formula: tn = a + d(n −1) Then, sub in all known values. tn = 15 (last term of the sequence), a = 1 (first term), d = 2 (difference between terms) and solve for n like so: 15 = 1 + 2(n −1)
In an ap the sum of first 10 terms is - 150
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WebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty …
WebThe sum of n terms of an AP can be easily found out using a simple formula which says that, if we have an AP whose first term is a and the common difference is d, then the formula of the sum of n terms of the AP is S n = … Webgiven S10 = a1+a2+...+10 = 150 But we know that: s10 = (a1+a10)*10/2 = 150 ==> a1+a10 = 150/5 ==> a1+a10 = 30 ==> a10 = 30 - a1...... (1) But a10 = a1 + 9*3 = a1 + 27 ==> a10 = 27 +...
WebIn an AP, the first term is −4, the last term is 29 and the sum of all its terms is 150. Find its common difference. [CBSE 2011] Open in App. Solution. Suppose there ... The sum of the first 9 terms of an AP is 81 and that of its first 20 terms is 400. Find the first term and the common difference of the AP. [CBSE 2009] View More. WebApr 2, 2024 · The median of the distribution given below is 14.4. Find the values of x and y, if the sum of frequency is 20. Find the common difference ' d ' of an AP whose first term is 10 and the sum of the first 14 terms is 1505 . For what value of ' n ', are the nth terms of the APs : 9,7,5,….. and 15,12,9,…. the same?
WebAnswer (1 of 5): 15+30+45 … +150 is an AP, whose first term, a = 15 and the common difference = 15. Tn = 150 = a+(n-1)d = 15 + (n-1)*15, or dividing right through by 15, 10 = 1 + (n-1), or n = 10 Sn = (n/2)[2a + (n-1)d] S10= (10/2)[2*15 + …
WebGiven that sum of the first 10 terms of an A.P. is -150. S 10 = -150 And the sum of next 10 terms is -550. So, the sum of first 20 terms = Sum of first 10 terms + sum of next 10 … small complex baker\u0027s cystWebOct 20, 2024 · Let a be the first term and d be the common difference of the given AP . S₁₀ = -150. ⇒ Sn = n/2 [ 2a + (n-1)d] ⇒ S₁₀ = 10/2 [ 2a + ( 10 - 1 ) d ]. ⇒ -150= 10/2 [ 2a + 9d ] ⇒ … small compass rose inlaysWebOct 10, 2024 · Academic Mathematics NCERT Class 10 Given: In an A.P., the sum of first ten terms is -150 and the sum of its next ten terms is -550. What to do: To find the A.P. … small compass tattoo for menWebFeb 17, 2024 · Sum of first 10 terms = -150. hence we have (10/2) [ 2a + 9d ] = -150 or 2a + 9d = -30 ..................... (1) next 10 terms gives total = -550 . Hence sum of 20 terms = -150 … small compartment box lockersWebApr 11, 2024 · Given the sum of the first 10 terms of an AP is -150 and the sum of the next ten terms which means Sum of first 20 terms - Sum of first 10 terms is -530. Let the first term, common difference of the AP be a and d respectively. Now, ⇒ S₁₀ = 10/2 [ 2a + (10 - 1)d ] ⇒ -150 = 5 [ 2a + 9d ] ⇒ 2a + 9d = -30 ...(i) Now, according to the second case, small comp help progsWebThe sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms. Q. small compartment fly boxWebOct 10, 2024 · In an A.P., the sum of first ten terms is -150 and the sum of its next ten terms is -550. Find the A.P. The sum of first q terms of an A.P. is 63 q – 3 q 2. If its p th term is − 60, find the value of p, Also, find the 11th term of … sometimes they come back wiki